How to capture a sentence but ignore whitespace more than 1 with regex?-CodePudding

My goal is to capture this string.

      04/07          TRSF E-BANKING DB                0207/QEZDF/WSA2321                                           500.00 DB
                     TANGGAL :02/07                   Q0344XXXXX12
                                                      SALZXA YAEAS SAX

What I've tried:

The regex used: (\d{2}/\d{2})([ ]{1,}[\w -]*)

However, the [\w -]* capture TRSF E-BANKING DB instead of just the TRSF E-BANKING DB.

I am not sure how to tell the regex within the match case that the whitespace length should not be more than 1.

CodePudding user response：

You can write the pattern as:

(\d{2}\/\d{2})  ([\w-] (?: [\w-] )*)

Explanation

(\d{2}\/\d{2}) Capture group 1, match 2 digits, / and 2 digits
Match 1 or more spaces
( Capture group 2
- [\w-] Match 1 word chars or -
- (?: [\w-] )* Optionally repeat matching 1 space and 1 or more word chars or -
) Close group 2

Regex demo