I have 4 different named log files, all with txt extensions. I need to write a bash script file that extracts JavaScript file names from any of these log files regardless of their names. The output of the script should not include the path, have to be unique, and sorted

After some research I came up with this:

cat logfile1.txt | grep '[^.(]*\.js' | awk -F " " '{print $7}' | sort | uniq -c| sort -nr

This code does only haft the job;

• PRO: It does extract any JS, sorts it, and gives unique results.

• CON: I need this in a file.sh not a command line as, it is now. Also, I'm getting the entire path to the JS file. I only need the file name jquery.js

I tried adding grep -v "*/name-of-path-before-JS" to block the result from giving me the full path but that isn't working.

I found someone who made something kind of similar using python; source

filenames = set()

with open(r"/home/filelog.txt") as f:
    for line in f:
        end = line.rfind(".js")   3 # 3 = len(".js")
        start = line.rfind("/", 0, end)   1 # 1 = len("/")
        filename = line[start:end]
        if filename.endswith(".js"):
            filenames.add(filename)


for filename in sorted(filenames, key=str.lower):
    print(filename)

Although is missing the sort and uniq options when giving the output it does give the results by only putting out filename.js and not the whole path as the command line I made. Also, I to add the path to the log.txt file while running the script and not just appended it as in the python script below.

Example; $./LogReaderScript.sh File-log.txt

CodePudding user response：

Would you please try the shell script LogReaderScript.sh:

#!/bin/bash

if [[ $# -eq 0 ]]; then                 # if no filenames are given
    echo "usage: $0 logfile .."         # then show the usage and abort
    exit 1
fi

grep -hoE "[^/] \.js" "$@" | sort | uniq -c | sort -nr

By setting the file as executable with chmod x LogReaderScript.sh, you can invoke:

./LogReaderScript.sh File-log.txt

If you want to process multiple files at a time, you can also say something like:

./LogReaderScript.sh *.txt

• -o option to grep tells grep to print the matched substrings only, instead of printing the matched line.
• -E option specifies extended regex as a pettern.
• -h option suppresses the prefixed filenames on the output if multiple files are given.
• The pattern (regex) [^/] \.js matches a sequence of any characters other than a slash, and followed by a extention .js. It will match the target filenames.
• "$@" is expanded to the filename(s) passed as arguments to the script.

CodePudding user response：

There's really no need to have a script as you can do the job with the oneliner, since you've mentioned you have multiple log files to parse i'm assuming this is a task you're doing on a regular basis.

In this case just define an alias in your .bashrc file with this oneliner:

cat $1 | awk '{print $7}' | grep '.js' | awk -F\/ '{print $NF}' | sort | uniq

Let's say you've created the alias parser then you'd just have to invoke parser /path/to/logfile.log

With the example logfile you've provided above, the output is:

➜  ~ cat logfile.txt | awk '{print $7}' | grep '.js' | awk -F\/ '{print $NF}' | sort | uniq
jquery.js
jquery.jshowoff.min.js
jshowoff.css

Explanation:

• cat is used to parse the file and then pipe the content into..
• awk which is extracting the 7th space separated field from the file, since those are apache access logs and you're searching for the requested file, the seventh field is what you need
• grep is extracting only the javascript files, ie. those ending with the .js extension
• awk is used again to print only the file name, we're defining a custom field separator this time with the -F flag, and executing the print command using the $NF argument which instructs awk to print only the last field
• sort and uniq are self explanatory, we're sorting the output then printing only the first occurrence for each repeated value.

jquery.jshowoff.min.js looked like bogus to me and i suspected i did something wrong with my commands, but it's an actual line (280) in your logfile

75.75.112.64 - - [21/Apr/2013:17:32:23 -0700] "GET /include/jquery.jshowoff.min.js HTTP/1.1" 200 2553 "http://random-site.com/" "Mozilla/5.0 (iPod; CPU iPhone OS 6_0 like Mac OS X) AppleWebKit/536.26 (KHTML, like Gecko) Version/6.0 Mobile/10A403 Safari/8536.25" "random-site.com"