I have a std::string named haystack, and I have a find() method to look for a substring in haystack:
size_t find (const string& needle, size_t pos = 0) const;
where pos is the position of the first character in haystack to be considered in the search.
But, one can specify only a start position, but not an end position, in std::string::find().
I am trying to find the best way to search only in a portion of haystack. That would consist of giving an end_pos to stop the search even though it doesn't reach the end of haystack.
For example, search only from its 100th character to its 200th character.
Does anybody know how I could achieve this (elegantly)?
- only by searching in
haystackitself, not in asubstr()of it - without creating a copy of
haystack - in C 98
CodePudding user response:
std::string does not have a method that suits your requirement to search a sub-range of the haystack string. Have a look at std::search() for that instead, eg:
std::string needle = ...;
std::string::iterator end_iter = haystack.begin() end_pos;
std::string::iterator found_iter = std::search(haystack.begin() start_pos, end_iter, needle.begin(), needle.end());
if (found_iter != end_iter) {
// needle found...
}
else {
// needle not found...
}
If your compiler does not have std::search() available, then just write your own search() function, such as with the implementation provided on cppreference.com, eg:
namespace my {
template<class ForwardIt1, class ForwardIt2>
ForwardIt1 search(ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last)
{
while (1) {
ForwardIt1 it = first;
for (ForwardIt2 s_it = s_first; ; it, s_it) {
if (s_it == s_last) return first;
if (it == last) return last;
if (!(*it == *s_it)) break;
}
first;
}
}
}
...
std::string needle = ...;
std::string::iterator end_iter = haystack.begin() end_pos;
std::string::iterator found_iter = my::search(haystack.begin() start_pos, end_iter, needle.begin(), needle.end());
if (found_iter != end_iter) {
// needle found...
}
else {
// needle not found...
}
