Use all types defined inside a class-CodePudding

I have a struct X defined, which defines some types inside of it:

struct X {
    using A = int;
    using B = double;
    // ...
};

Now, it is possible to use these types outside of the class using typename, e.g.:

typename X::A a = 3;
typename X::B b = 3.5;

My question: If X was a namespace, then it would have been possible to use using namespace X to avoid typing typename X::... all of the time, but since X is a class, then we cannot do that. Is there any way to use the namespace X in order to avoid typing typename X::... all of the time?

Doing something like using namespace X does not seem to work. It is possible to use a singular type, using something like using A = X::A however I want a way to do this automatically for all types defined within a class.

Note that X may be a templated class, if that matters.

CodePudding user response：

Namespaces are designed for that purpose and gives more possibilities than classes in that respect.

But no, there is no such thing as using classspace X; A a = 3; (or equivalent) for class-name scope.

Considering that using namespace ... is often considered a bad practice, I doubt it will come soon.