This is my simplified regex:

abc\((. ?)\)

I want to match like:

abc(wwww)). abc(wwww)).

See the result

I want to match the ) and everything after that at end of first match.

Include last ")"

Examples:

• ?text[.ev.wa.vew.av.ewa] => .ev.wa.vew.av.ewa
• ?text[hello$(abc)elv] => hello$(abc)elv
• ?text(just test[test]) => just test[test]
• ?text(test 2[test]here something) => test 2[test]here something

CodePudding user response：

You can use

\?text(?:\[([^\]\[]*)]|\(([^()]*)\)). 

See the regex demo. The results are either in Group 1 or Group 2 (you will need to check in the code).

Details

• \?text - a ?text text
• (?:\[([^\]\[]*)]|\(([^()]*)\)) - one of the two alternatives:`
  • \[([^\]\[]*) - [, zero or more chars other than [ and ] and then a ] char
  • | - or
  • \(([^()]*)\) - (, zero or more chars other than ( and ) and then a ) char
• . - one or more chars other than line break chars as many as possible.

Now, if you need to support nested brackets, you would need a recursion support, but Java regex does not provide such an option. Hence, the only regex way is to hardcode nested level support. Here is an example with one nested level:

\?text(?:\[([^\]\[]*(?:\[[^\]\[]*][^\]\[]*)*)]|\(([^()]*(?:\([^()]*\)[^()]*)*)\)). 

See the regex demo. You can add more levels.

CodePudding user response：

after reading the comments below try this: abc\(([^)] \)\([^)] \))

https://regex101.com/r/lC8UJb/2

using negated character classes like [^)] is a little safer thank .*? as it is more exact to what is usually desired.