How to show widget sent from another page based on a condition in flutter-CodePudding

I have a page that I use in common. I'm posting a "widget" named "custom widget" on this page. If "custom widget" is sent I want to show it. If it's not sent, don't do anything. How can I achieve this?

CodePudding user response：

use your custom widget like this:

customWidget != null ? Row(children: [customWidget!]) : Container()

CodePudding user response：

Check if the customWidget is null and show it if it's not.

customWidget ?? Container()

CodePudding user response：

you can use the if condition like below.

Row(
  children: [
    if (customWidget != null) customWidget,
  ],
),