Suppose I have two arrays of different sizes. Say A=[10;12;13;17;18]; and B=[20;22;23;17;26;30;32];. The output, C will be as follows:
[10, 8, 7, 3, 2;
12, 10, 9, 5, 4;
13, 11, 10, 6, 5;
7, 5, 4, 0, -1;
16, 14, 13, 9, 8;
20, 18, 17, 13, 12;
22, 20, 19, 15, 14].
Each column of C is obtained by taking difference between all elements of B with a specific element of A. For example, the first column of C is obtained by taking the difference of all elements of B with first element of A, i.e., 10. If the dimension of A is (m-by-1) and B is (n-by-1), then C will have dimension (n-by-m).
CodePudding user response:
you can use this block of code.
clear;
clc;
A=[10;12;13;17;18];
B=[20;22;23;17;26;30;32];
m = length(A);
n = length(B);
C = zeros(n,m);
for i=1:m
for j=1:n
C(j,i) = B(j) - A(i);
end
end
disp(C)
