Selenium: finding element-CodePudding

There is nesting:

<div class = "top">
   <div>
      <span > </span>
      <span > </span>
      <span > </span>
   </div>
</div>  
 
<div >
   <div>
      <span > </span>
      <span > </span>
      <span > </span>
   </div>
</div>

It is necessary to take the "bottom" elements in blocks one by one, based on the "top", but this entry returns an empty list.

for i in range(2):
      elements = browser.find_elements_by_xpath("//div[@class='top']["   str(i) "]//span[@class='bottom']") 
      print(elements)

What's my mistake?

CodePudding user response：

To get bottom elements per top blocks here you can use this XPath:

for i in range(1,3):
      elements = browser.find_elements_by_xpath("(//div[@class='top'])["   str(i)   "]//span[@class='bottom']")

CodePudding user response：

Why not retrieve all elements and iterate over them instead?

elements = browser.find_elements_by_xpath('//div[@]/span[@]')
for element in elements:
    if element:  # some invalidating condition
        continue
    print(element)  # success!

This way selectors are much more efficient as you onyl need to execute 1 selector rather than N selectors. Also, note that xpath is pretty powerful - maybe you can integrate selection logic in the xpath itself?

See live xpath tester