Remove brackets from strings with regex in Python-CodePudding

Currently, I have two string with bracket

'NI,DG,BJ (1).jpg','N1,DG,BJ(1).jpg'

For each string, I want to split and obtain each character split by the comma, except for the enclosing bracket.

This is achieable via the following

import re
s=['NO,AG,GK.jpg','NI,DG,BJ (1).jpg','N1,DG,BJ(1).jpg']

all_v=[]
for d in s:
  k=re.sub("(\s\(\d \))?(\.jpg)?", "", d).split(',')

  if '(' in k[-1] :
    k[-1]=k[-1].split('(')[0]

  all_v.append(k)

But, since the bracket can be close or separated by space, I have to add if statement.

I wonder whether there is regex smart way to skip the if-else statement

Expected output

['NO', 'AG', 'GK']
 ['NI', 'DG', 'BJ']
 ['N1', 'DG', 'BJ']

CodePudding user response：

import re
s=['NO,AG,GK.jpg','NI,DG,BJ (1).jpg','N1,DG,BJ(1).jpg']

for i in s:
    [re.search('(\w ).*',k).group(1) for k in i.split(',')]

rsults

['NO', 'AG', 'GK']
['NI', 'DG', 'BJ']
['N1', 'DG', 'BJ']