How to compare list of dicts in Python-CodePudding

I have below list:

objList = [{
            'Name': 'keyboard',
            'objectId': [0, 1],
            'StartTime': '2022-01-10T13:18:17.098119',
            'IsCompleted': False,
            'MetaData': [{
                'Count': 2
            }]
}]


o = [{"keyboard": "Assembly"}, {"smallObjects": "Label"}]

I have to check if objList has all the dict with Name matching the key of dict in o. If not then print the Name. I have below working code:

if len(objList) != len(o):
    for i in o:
        for (k, v) in i.items():
            for obj in objList:
                if k == obj["Name"]:
                    print("Found {}".format(k))
                else:
                    print("Not found {}".format(k))

It seems to be working but not properly optimized as it has lot of for loop. Is there any other way we can optimize the code. Thanks

CodePudding user response：

another way to resolve your problem is to trap all keys and all values for key Name in 2 sets/lists, like this:

objList = [{
            'Name': 'keyboard',
            'objectId': [0, 1],
            'StartTime': '2022-01-10T13:18:17.098119',
            'IsCompleted': False,
            'MetaData': [{
                'Count': 2
            }]
}]
o = [{"keyboard": "Assembly"}, {"smallObjects": "Label"}]

all_keys = set().union(*(d.keys() for d in o))
names=[d['Name'] for d in objList]

for k in all_keys:
    if k in names:
        print("Found {}".format(k))
    else:
        print("Not found {}".format(k))