Python3 Datetime (delta) to Seconds (Including Days)-CodePudding

Hopefully just a simple question. I want to convert a datetime object to seconds and include the days. I've just noticed that my code skipped the day. Please note times are just an example and not 100% accurate.

Content of oldtime.txt (2 days ago):

2021-09-16 19:34:33.569827

Code:

oldtimefile = open('oldtime.txt', 'r ')
oldtme = oldtimefile.read()
datetimeobj = datetime.strptime(oldtme, "%Y-%m-%d %H:%M:%S.%f")
finaltime = datetime.now() - datetimeobj
print(finaltime.seconds)

If I just print finaltime then I get 1 day, 22:13:30.231916.

Now if we take today's date and time - just for argument sake - (2021-09-18 17:34:33.569827) as now then I actually get 80010 seconds instead of roughly 172800 seconds. It's ignoring the day part.

How can I include the day and convert the entire object to seconds?

Thanks.

CodePudding user response：

Instead of .seconds you can use .total_seconds():

from datetime import datetime

oldtme = "2021-09-16 19:34:33.569827"
datetimeobj = datetime.strptime(oldtme, "%Y-%m-%d %H:%M:%S.%f")
finaltime = datetime.now() - datetimeobj
print(finaltime.total_seconds())

Prints:

164254.768354