Javascript RegEx to match all whitespaces except between special characters-CodePudding

I need a regEx to match all whitespaces except those inside @ signs to make a correct split.

I have this string:

[0] == @Item 1@

With the split I need the following array (with or without @ in 3rd element):

var array = ["[0]","==","@Item 1@"];

With a simple split(" ") I get this:

var array = ["[0]","==","@Item","1@"];

Thank you for your help.

CodePudding user response：

You can use

const text = '[0] == @Item 1@';
console.log( text.match(/(?:@[^@]*@|\S) /g) )

See the regex demo. The (?:@[^@]*@|\S) pattern means:

(?: - start of a non-capturing group:
- @[^@]*@ - a @ char, zero or more chars other than @ and then a @ char
- | - or
- \S - any non-whitespace char
) - end of the group, repeat one or more times.

The /g flat tells .match() to extract all occurrences.

CodePudding user response：

I don't know if you need just 3 elements in the array, if so you can try

string.split(" ", 3)