Sort dict by a dict value-CodePudding

I'm trying to sort a dict's value where the value is a dict where the value is a list of two integers. I'm trying to sort the rows in the inner dict by the first integer of the list.

This is the value of the dict:

{'EQUITY': {'CA': [15, 20], 'US': [25, 30]}, ... }

Here, the 'US' row should come before the 'CA' row after sorting.

This is what I'm currently trying:

dict(sorted(data.items(), key=lambda item: item[1][ ?? ], reverse=True))

how should I index into the inner dict from here ??

Thanks in advance for the help.

CodePudding user response：

You are almost there. Try the following, which uses dict comprehension and sorted with key parameter:

dct = {'EQUITY': {'CA': [15, 20], 'US': [25, 30]}, 'FUTURE': {'CA': [5, 5], 'US': [10, 2]}}

output = {k: dict(sorted(d.items(), key=lambda item: item[1][0], reverse=True)) for k, d in dct.items()}

print(output)
# {'EQUITY': {'US': [25, 30], 'CA': [15, 20]}, 'FUTURE': {'US': [10, 2], 'CA': [5, 5]}}

Here, each item of d.items() would be a tuple like ('CA', [15, 20]). Therefore, to sort by 15, you need item[1][0].