Can someone help and kindly advise how Can I get specific values from this dictionary (Using list comprehension) and

1. square the values only,
2. change every string value, so it starts with upper case?

items_list = {'a': 3, 'b':6, 'c': 'short', 'h': 'example', 'p': 77}

So, the output needs to be:

9, 36, 5929
Short, Example

CodePudding user response：

(Python):

items_list = {'a': 3, 'b': 6, 'c': 'short', 'h': 'example', 'p': 77}

lst = [v ** 2 if isinstance(v, (int, float)) else v.capitalize() for v in
       items_list.values()]

print(lst)

output:

[9, 36, 'Short', 'Example', 5929]

The exact output that you showed can not be produced using single list comprehension, because the iteration is in order.

CodePudding user response：

yes, you need to iterate through the dictionary and check if the value is an int then square it and if it is not capitalize it

result = []
for key, value in dictionary.items()
    if type(value) is int:
        result.append(value**2)
    else:
        result.append(value.capitalize())
print(result)

this should print the desired output