I have to check if a string follows the following patterns:
Field1=value1
Field1=value1,Field2=value2
7645a=fds23,Field2=dsd$
The words 'field1', 'value1' don't count, the important thing is that it has to be something=something and if there is more than 1, it should be a comma for each pair.
I reached the following regex:
((\w )[^=])=((\w )[^=])
"Match any one or more word except if it has =, then there should be an = and then match any one or more word except if it has =".
The thing is, it does take the comma but I think is because of \w. I don't think this is correct.
I'm using https://regexr.com/ to check for the correct regular expression.
CodePudding user response：
If you need to match symbols like $, then don't use \w. This satisfies all your conditions:
(?:([^,=\n] )=([^,=\n] ))(?:,([^,=\n] )=([^,=\n] ))*
Explanation:
(?: // Begin non-capturing group (first key=value pair)
( // Begin capturing group (key)
[^,=\n] // Match one or more characters that aren't comma, equals, or new line
) // End capturing group (key)
= // Equals
( // Begin capturing group (value)
[^,=\n] // Match one or more characters that aren't comma, equals, or new line
) // End capturing group (value)
) // End non-capturing group (first key=value pair)
(?: // Begin non-capturing group (additional key=value pairs)
, // Starts with comma (otherwise entire group fails)
( // Begin capturing group (key)
[^,=\n] // Match one or more characters that aren't comma, equals, or new line
) // End capturing group (key)
= // Equals
( // Begin capturing group (value)
[^,=\n] // Match one or more characters that aren't comma, equals, or new line
) // End capturing group (value)
) // End non-capturing group (additional key=value pairs)
* // Match 0 or more of the additional key value pairs