how cut strings after a specific word?-CodePudding

i have a columns of texts. How I can cut the part of each text after the term show less?

For example:

df = pd.DataFrame({'col':['hi there see less new way is comming','today is summer, see less , is a lovely day']})

that looks like:

col 
'hi there see less new way is comming'
'today is summer, see less , is a lovely day'

output:

col 
'hi there'
'today is summer,'

CodePudding user response：

You can use str.split to split on see less and then use str slicing to take the first part.

df['col'] = df['col'].str.split('see less').str[0]

Output:

                 col
0          hi there 
1  today is summer,

CodePudding user response：

You can use a simple regex and str.replace:

df['col'] = df['col'].str.replace('see less.*', '', regex=True)

output:

                 col
0          hi there 
1  today is summer,

If you also want to remove the non-letter character just before:

df['col'].str.replace(r'\W see less.*', '', regex=True)

output:

               col
0         hi there
1  today is summer

CodePudding user response：

Use str.extract:

df['col'] = df['col'].str.extract('(.*)\s*see less')
print(df)

# Output
                 col
0          hi there 
1  today is summer,