Python - Split String correctly-CodePudding

string = 'ESO 12-4 356.0648792 -80.1770250'

I want it to be broken down into a list like this:

list = ['ESO 12-4', '356.0648792', '-80.1770250']

However, the first part ('ESO 12-4') can have multiple strings, so I thought to cut it off from the end.

My Code:

print(string.split(' ')[-2:])

Output:

['356.0648792', '-80.1770250']

CodePudding user response：

I am assuming that you always have the string with the following format.

your_string = '<FIRST_PART(CAN CONTAIN SPACES)> <SECOND_PART(WITHOUT SPACES)> <THIRD_PART(WITHOUT SPACES)>'

If yes you could use rsplit(maxsplit=2) to get the desired output.

>>> string = 'ESO 12-4 356.0648792 -80.1770250'
>>> string.rsplit(maxsplit=2)
['ESO 12-4', '356.0648792', '-80.1770250']

CodePudding user response：

Im new in python, i love @Abdul Niyas P M @Selcuk answers.

string = 'ESO 12-4 356.0648792 -80.1770250'
l = len(string.split())
print(string.rsplit(maxsplit=l-2))

#['ESO 12-4', '356.0648792', '-80.1770250']

CodePudding user response：

You can reverse the string and use the maxsplit argument of the .split() method. Obviously you should also reverse the result in the end. Try this:

>>> [s[::-1] for s in string[::-1].split(" ", 2)[::-1]]
['ESO 12-4', '356.0648792', '-80.1770250']

Edit: You should probably use the .rsplit() method as @AbdulNiyasPM posted instead of using this convoluted method.

CodePudding user response：

You can use regexp to extract the "12-4" and use it to split the string

>>>import re
>>>string = 'ESO 12-4 356.0648792 -80.1770250'
>>>matched_string = re.findall(r'[0-9] -[0-9] ', string)[0]
>>>[string.split(matched_string)[0]   ' '   matched_string, string.split(' ')[-2] , string.split(' ')[-1]])
['ESO  12-4', '356.0648792', '-80.1770250']