I want to simplify this if-Statement and prevent writing "!='*'" three times. Is it possible?

if (i != '*' && j != '*' && k != '*')

CodePudding user response：

1. use arrays：put all elements into the array, traverse the array and judge。

List<String> list = new LinkedList<>(Arrays.asList(i,j,k));
if(list.stream().noneMatch("*"::equals)){

}else{

}

2. use string: splice elements into a string

String temp = i j k;
if(temp.contains("*")){
}

CodePudding user response：

Yes it is possible to omit writing !='*' three times but the method will be still longer one. I would suggest to use the method which you have written in your question but if you really want to try something other out (maybe out of curiosity), you can do this:

char ch[] = {i,j,k};    /*I hope the variables i,j,k in question are char type*/
boolean flag = false;
for(int t = 0; t < ch.length; t  ){
    if(ch[t] != '*')
        flag = true;
    else{
        flag = false;
        break;
    }
}
if(flag){
    //Tasks to do...
}

Writing this much is a tedious job. Thus, if (i != '*' && j != '*' && k != '*') is the most optimised one. So I would recommend using it.