I have a table
| senderId | receiverId | date |
|---|---|---|
| 1 | 2 | "2022-08-10T07:21:12.881Z" |
| 2 | 1 | "2022-08-10T07:28:12.881Z" |
| 2 | 1 | "2022-08-10T07:22:12.881Z" |
| 1 | 2 | "2022-08-10T07:25:12.881Z" |
Current query
SELECT DISTINCT ON ("senderId", "receiverId") "sender"."id" AS "senderId", "receiver"."id" AS "receiverId", cm."createdAt" AS "createdAt" FROM "chat_message" "cm" LEFT JOIN "user" "sender" ON "sender"."id"="cm"."senderId" LEFT JOIN "user" "receiver" ON "receiver"."id"="cm"."receiverId" WHERE "senderId" = 2 OR "receiverId" = 2 ORDER BY "senderId", "receiverId" ASC, cm."createdAt" DESC
Current result
| senderId | receiverId | date |
|---|---|---|
| 1 | 2 | "2022-08-10T07:25:12.881Z" |
| 2 | 1 | "2022-08-10T07:28:12.881Z" |
Expected result
| senderId | receiverId | date |
|---|---|---|
| 2 | 1 | "2022-08-10T07:28:12.881Z" |
So, I need to select only one row in this pair where the date is bigger
CodePudding user response:
We can use a LEAST/GREATEST trick here along with DISTINCT ON:
SELECT DISTINCT ON (LEAST(senderId, receiverId),
GREATEST(senderId, receiverId))
LEAST(senderId, receiverId) AS senderId,
GREATEST(senderId, receiverId) AS receiverId,
createdAt
FROM chat_message
ORDER BY 1, 2, createdAt DESC;
