Login Failed Error Message Django Based Views-CodePudding

I have a project made with function based views. I need to show an error message when the user enters the wrong password, but in every forum I've seen so far there is a suggestion to use a Form. There is no way to show an error message with the project done this way?

view.py:

def login(request):
     if request.method == "GET":
          return render(request, 'users/login.html')
     else:
          Email = request.POST.get('Email')
          Senha = request.POST.get('Senha')
          user = authenticate(username=Email, password=Senha)

          if user:
               loginDjango(request, user)
               return render(request, 'convite/cadastro_convite.html')
          else:
               return redirect('login')

html:

<div >
     <h2 >Faça seu login!</h2>
     <form  action="{% url 'login'%}" method="POST"> 
          {% csrf_token %}

          <div >
               <input type="text"  id="log-email" aria-describedby="emailHelp" name="Email" placeholder="Email">
          </div>

          <div >
               <input type="password"  id="log-senha" name="Senha" placeholder="Senha">
          </div>

          <button href="/Exemplo" type="submit" >
               <i ></i> Acessar
          </button>
     </form>
</div>

model:

from django.contrib.auth.models import AbstractUser
from django.db import models

class User(AbstractUser):
    NomeUsuario = models.TextField(blank=True)
    Endereco = models.TextField(blank=True)
    Celular = models.TextField(blank=True)
    Cidade = models.TextField(blank=True)
    Estado = models.TextField(blank=True)
    Cep = models.TextField(blank=True)
    Bairro = models.TextField(blank=True)

CodePudding user response：

While it seems using a django form is more efficient, yes there is a way you could do it from what you have by just adding a few lines of code.

But here's my first recommendation... Rename your defined method called login to loginDjango. By doing that you could use the django login method without having any potential issues.

You can use the code below to solve your problem:

from django.contrib.auth import login, get_user_model
from django.shortcuts import get_object_or_404


def loginDjango(request):
     context = {}         

     if request.method == "GET":
          return render(request, 'users/login.html', context)
     else:
          found = False

          Email = request.POST.get('Email')
          Senha = request.POST.get('Senha')
          
          # Try retrieving the user object from the get_user_model method
          user = get_object_or_404(get_user_model(), email=Email) # Assuming the email field is unique.

          # If a user object was returned then you can use the check_password method on the user object.
          if user:
               if user.check_password(Senha): # If the passwords matched
                    found = True
               else:
                    context['password_error'] = 'You have entered an incorrect password!'
          else:
               context['email_error'] = "Sorry, this email address doesn't exist!"
          
          # If the email exists and the password match then found is true...
          # Can use the authenticate within this if statement
          if found:
               # From the user object, using user.username -> username=user.username
               user = authenticate(username=user.username, password=Senha)
               
               # This if statement is not really necessary again but you can have it as a fail-safe
               if user:
                    # Use the django login method to log the user in.
                    login(request, user)
                    return render(request, 'convite/cadastro_convite.html')
          
          return render(request, 'users/login.html', context)

Then within your template, you can check for the errors you sent via the context dictionary.

<div >
     <input type="text"  id="log-email" aria-describedby="emailHelp" name="Email" placeholder="Email">
     {% if email_error %}<span>{{ email_error }}</span>{% endif %}
</div>

<div >
     <input type="password"  id="log-senha" name="Senha" placeholder="Senha">
     {% if password_error %}<span>{{ password_error }}</span>{% endif %}
</div>

But I do recommend that you give doc a read for the djano forms as well though.

CodePudding user response：

The easier way to do this is using Django messages Framework

from django.contrib import messages

messages.info(request, '#message you want to show in the template')

You can use For Loop or If statement

Like:

{% for message in messages %}

 <p>{{message}}></p>

{% endfor %}