My task is to grab latest version of maven in bash script using curl https://apache.osuosl.org/maven/maven-3/ Output should be: 3.8.5

CodePudding user response：

One way is to

• Use grep to only get the lines containing the folder link
• Use sed with an regex to get only the version number
• Use sort to sort the lines
• Use tail -n1 to get the last line

curl -s https://apache.osuosl.org/maven/maven-3/ \
    | grep folder \
    | gsed -E 's/.*([[:digit:]]\.[[:digit:]]\.[[:digit:]]).*/\1/' \
    | sort \
    | tail -n1

Output:

3.8.5

CodePudding user response：

Using sed and tac

• -s in curl command to silence output
• tac reverse order of file
• /^<img src/{s/\([^>]*>\)\{2\}\([^/]*\).*/\2/p;:a;n;ba} Match lines starting with <img src then extract the first match

$ curl -s https://apache.osuosl.org/maven/maven-3/ | tac | sed -n '/^<img src/{s/\([^>]*>\)\{2\}\([^/]*\).*/\2/p;:a;n;ba}'
3.8.5