Im trying to get an if statement to reply to a random number in python and display and print a messa-CodePudding

I'm trying to get an if statement to recognize a randomly generated number but I don't know what is going wrong, it just ends the program as soon as i hit start and does not print anything, so far I have this.

import random

random.randint(1,3)

if random.randint == ('1'):
    print('message')

I have tried changing the random.randint(1,3) into a variable by making it "a == ('random.randint(1,3)" but that did not work either. Does anyone know whats going wrong with it?

P.S: Sorry if the question is asked badly, I don't use this site much.

CodePudding user response：

There are several problem with your code.

randint() creates a number like 1. It will never make a string like '1'. Additionally random.randint is a function. random.randint == ('1') will never be true, because a function is never never be equal to a number or a string. You want to compare the result of calling the function to an integer.

import random

num = random.randint(1,3)

if num == 1:
    print('message')

CodePudding user response：

random.randint() is a function - therefore, you have to save its output in a variable, or else the value will be lost. For instance:

import random

rand_num = random.randint(1,3)

if rand_num == 1:
    print('message')