I am trying to do a bash script that loop through a folder and it s subfolder and print files. This part is working, but I try to put this part in an if condition and that seems I was not able to..

What I want is that on every 10 files found to sleep 10 seconds and then start again from where were left (continue)..

this is what I did

#!/bin/bash

declare -i x=0
    
if (( $x < 10  )); then
    
find /myfolder -type f -maxdepth 5 | while read file; do
  echo $file;
  ((x  ))
echo $x;

done

else

echo "found 10";
sleep 10;
$x=0;

fi

CodePudding user response：

I'd do it like this:

while IFS= read -rd '' file; do
    printf '%s\n' "$file"
    ((  i % 10)) || sleep 10
done < <(find /myfolder -maxdepth 5 -type f -print0)

This uses process substitution, -print0, IFS= read -rd '', and printf instead of echo to allow for all legal characters in filenames.

The important line is

((  i % 10)) || sleep 10

This adds 1 to i, then checks if i is now a multiple of 10. Since the remainder is non-zero when i is not a multiple of 10, (( i % 10)) evaluates to true (exit status of 0), and nothing happens. When i is a multiple of 10, (( i % 10)) becomes ((0)), which has a non-zero exit status, and sleep 10 is executed.

Why your approach doesn't work:

Once you have checked if x is less than 10, you run the find | while ...; do ... done command entirely – there is never any check for the value of x until it's done.