Regex Match anything inside the string-CodePudding

How Can I match XX.Xx("$\bH.Pt#S V0&DJT-R&", gM) this pattern in a string shown below, the only constant is XX. two arguments are random

XX.Xx("$\bH.Pt#S V0&DJT-R&", gM)
XX.Vx("\'\x40]\tFv9](H\x40J[)", F6)

[XX.Ux("gI\ny", sl), Ar, XX.Rx("\t|", pO), Jd, XX.kx("xW\n", CM), Wm, XX.wx("U\vyV", DO), jr, XX.Mx("U\vxW", GO), Zm, XX.tx("a{O", xO), Hm, XX.RV(Qk, Hl, Q0), Qd, XX.Nx("\t|", OM), Br, XX.zx("{I\v", vM), jd, XX.gx("U\vxS", W6), nm, XX.kV(Qk, UM, Q0), Bd, XX.rx("\t|", RM), Xm, XX.mx("V\r", kM), Id, XX.dx("J\t~", KY), Lm, XX.hx("xV\v", wN), Sd, XX.bx("xU\x00", d6), rd, XX.Cx("axK", BM), Wd, XX.qx("}~", h6), Zd, XX.sx("gI\b", b6), Hd, XX.Kx("xU", C6), Lh, XX.Wx("U\ry", q6), pm["fpValStr"], XX.wV(Qk, Ml, F0), vd, XX.Zx("sH", LN), jm, XX.Hx("{I\f", jM), Xh], Vh && (Wr.push(XX.nx("xT", XN), XX.Ax("", VN)), Th = j3(N3)), Wr.push(XX.Fx("J\nu", nY), Md), Kr = ph(j2, [Wr, A0]), Dh = Wr.join(Kr), qr(XX.Ex("9I\x00", TN).concat(Dh["slice"](N3, W0)));

https://regex101.com/r/Ui71E9/1

CodePudding user response：

(XX\.[A-Za-z]*$"([^"]*)",\s*([0-9A-Za-z]{2})$,\s*[0-9A-Za-z)] )

To capture multiple times

run the regexp on the big string
if no matches, break
use the second and third capture groups as you like
get the first capture group
in the big string replace that capture group with an empty string
do it again with the modified string

Old Answer

XX\.[A-Za-z]*$"(.*)",\s*([0-9A-Za-z]{2})$

I included capture groups if your interested

I can explain it if you'd like

XX\. The beginning is probably obvious. XX\.
- it's important to note that . in regex matches anything, however I assume you specifically want to get a period. Thus we escape it like \.
[A-Za-z]* next we are matching any amount of characters from capital A to capital Z and lower case a and lowercase z. I assume that it will always be 2 characters but I'll let it slide for now
\( next we escape the open parenthesis because parenthesis represents a capture group
" next we look for a quotation mark
(.*)" next we capture anything intil we hit another quotation mark.
- It's important to note that if the string has an escaped quotation mark, this regexp breaks. If you need an escaped quotation mark also I'll try to help you out
, next we look for a comma
\s* after that we look for any amount of spaces. Could be zero, could be a hundred
(0-9A-Za-z){2} next we capture two characters that could be 0-9 A-Z and A-Z
\) finally we end with a parenthesis