Print details of an employee by entering the name of employee in Python-CodePudding

I am getting input of details of the employee from the user and then asking the user to enter the name of the employee, he wants to retrieve information of. I am saving all the entered data in a dictionary with employee name as its key and [employee_id, salary, address] as the values. Now whatever name I enter to retrieve the details, the output is always the details of the last entered employee.

    n = int(input('Enter the number of employee: '))
    employees = {}
    
    for i in range(n):
        name = input('Enter the name of the employee: ')
        emp_id = input("Enter employee Id: ")
        sal = int(input("Enter the employee salary: "))
        address = input('Enter the employee address: ')
        employees[name] = [emp_id, sal, address]
    
    while True:
        name = input('Enter employee name: ')
        info = employees.get(name, -1)
        if info == -1:
            print('Employee does not exist')
        else:
            print('Employee details are: \n Employee Id: ', emp_id, '\n Salary: ', sal, '\n Address: ', address)
        
        exit_choice = input('Do you want to exit [Yes|No]: ')
        if exit_choice == 'No' or exit_choice == 'no':
            break

I want to get the output as the details of the employee whose name is entered. Please can you help me get out of this situation?

CodePudding user response：

You're not printing the information you got from the dictionary. You need to get that from info.

   while True:
        name = input('Enter employee name: ')
        info = employees.get(name, -1)
        if info == -1:
            print('Employee does not exist')
        else:
            emp_id sal, address = info
            print('Employee details are: \n Employee Id: ', emp_id, '\n Salary: ', sal, '\n Address: ', address)
        
        exit_choice = input('Do you want to exit [Yes|No]: ')
        if exit_choice == 'No' or exit_choice == 'no':
            break

CodePudding user response：

I would do the following:

while True:
    name = input('Enter employee name: ')
    info = employees.get(name, -1)
    if info == -1:
        print('Employee does not exist')
    else:
        print(f'Employee details are: \n Employee Id: {info[0]} \n Salary: {info[1]} \n Address: {info[2]}')
    #And then the exit thing

CodePudding user response：

a lots of bug in your code, the correct code will be,

n = int(input('Enter the number of employee: '))
employees = {}
    
for i in range(n):
    name = input('Enter the name of the employee: ')
    emp_id = input("Enter employee Id: ")
    sal = int(input("Enter the employee salary: "))
    address = input('Enter the employee address: ')
    employees[name] = [emp_id, sal, address]

while True:
    name = input('Enter employee name: ')
    info = employees.get(name, -1)
    if info == -1:
        print('Employee does not exist')
    else:
        print(f'Employee details are: \n Employee Id: {info[0]}\n Salary: {info[1]}\n Address: info[2])')
    
    exit_choice = input('Do you want to exit [Yes|No]: ')
    if exit_choice == 'Yes' or exit_choice == 'yes':
        break