When building array program in Java, it does not return the last number of the array when following-CodePudding

I am writing a small program to take an input array, nums and create a new array that is double the size and returns the last number from the previous array as the last and only different number in the new array.

When I try to return this number using the nums.length - 1 formula to get the end of the array, it returns the number in the middle of the new array. Below is my program.

public int[] makeLast(int[] nums) {
    
    int lengonewarr = nums.length;
    
    int officiallength = lengonewarr * 2;
    
    
    int [] makezero = new int [officiallength];
    
    makezero [nums.length-1] = nums[nums.length-1];
    
    return(makezero);
  
}

These are the outputs I should be making:

makeLast([4, 5, 6]) → [0, 0, 0, 0, 0, 6]
makeLast([1, 2]) → [0, 0, 0, 2]
makeLast([3]) → [0, 3]

But I instead get something like:

makeLast([1, 2, 3, 4]) → [0, 0, 0, 0, 0, 0, 0, 4] (My output) [0, 0, 0, 4, 0, 0, 0, 0]  
makeLast([2, 4]) → [0, 0, 0, 4]  (My output)    [0, 4, 0, 0]

Any advice is greatly appreciated.

CodePudding user response：

the array makezero's length is officiallength, not nums.length, just replace the first nums.length by makezero.length or officiallength.

makezero [makezero.length -1] = nums[nums.length-1];

BTW: It's better to name the variable with camelCase style, which will make the code more readable. Like makeZero or officialLength

CodePudding user response：

I modified your and here it is:

public int[] makeLast(int[] nums) {
    
    int lengonewarr = nums.length;
    
    int officiallength = lengonewarr * 2;
    
    int [] makezero = new int [officiallength];
    
    makezero [makezero.length-1] = nums[nums.length-1];
    
    return(makezero);
  
}

As the array makezero is double size, the length of lengonewarr is always in the middle of makezero.