Split text in hash value into new hash using separator in Ruby-CodePudding

I found another question similar to the one I have, but I was not able to replicate it (probably because it doesn't deal with hashes neither have symbols).

So, given the following array of hashes:

[{:id=>1, :name=>"AA;AB;AC", :title=>"A row"},
 {:id=>2, :name=>"BA;BB", :title=>"B row"},
 {:id=>3, :name=>"CA", :title=>"C row"}]

I would like to achieve the following result:

[{:id=>1, :name=>"AA", :title=>"A row"},
 {:id=>1, :name=>"AB", :title=>"A row"},
 {:id=>1, :name=>"AC", :title=>"A row"},
 {:id=>2, :name=>"BA", :title=>"B row"},
 {:id=>2, :name=>"BB", :title=>"B row"},
 {:id=>3, :name=>"CA", :title=>"C row"}]

In brief, I want to fully replicate a hash, splitting it by semicolon. In this case, :name have two hashes with one or more semicolons that should be split and consist on another hash.

I hope you have understand my question. Any help is highly appreciated.

CodePudding user response：

You could iterate over your array of hashes and split their name value, and map that result merging it with the current hash. Then you can flatten the result:

[
  {:id=>1, :name=>"AA;AB;AC", :title=>"A row"},
  {:id=>2, :name=>"BA;BB", :title=>"B row"},
  {:id=>3, :name=>"CA", :title=>"C row"}
].flat_map do |hsh|
  hsh[:name].split(";").map do |name|
    hsh.merge(name: name)
  end
end

# [{:id=>1, :name=>"AA", :title=>"A row"},
#  {:id=>1, :name=>"AB", :title=>"A row"},
#  {:id=>1, :name=>"AC", :title=>"A row"},
#  {:id=>2, :name=>"BA", :title=>"B row"},
#  {:id=>2, :name=>"BB", :title=>"B row"},
#  {:id=>3, :name=>"CA", :title=>"C row"}]

CodePudding user response：

Using Enumerable#each_with_object

ary =
  [
    { id: 1, name: "AA;AB;AC", title: "A row" },
    { id: 2, name: "BA;BB", title: "B row" },
    { id: 3, name: "CA", title: "C row" }
  ]

ary.each_with_object([]) do |hash, new_ary|
  hash[:name].split(";").each do |name|
    new_ary << hash.merge(name: name)
  end
end