I am working on the Free Code Camp Javascript phone number validation project. There is a phone number that I need to pass through my code to change to proper formatting that contains more than 1 set of parentheses: (555)5(55?)-5555.
How do I match 2 or more instances of each type of parentheses? For example, I want to find 2 or more instances of "(" or 2 or more instances of ")" anywhere in the string.
I tried the following regex and it did not work:
/\({2,}|\){2,}/
Thanks in advance for any guidance, I am very new to Regex.
CodePudding user response：
You can use /\(.*?\)/g to get the match and then use length to get the count.
const str = '(555)5(55?)-5555';
const result = str.match(/\(.*?\)/g)?.length;
if (result >= 2) console.log('Valid');
else console.log('Not Valid');The above will still pass the test if you are testing against const str = '()5555(55?)-5555';
In that case you can use /\(. ?\)/g as:
const str = '()5555(55?)-5555';
const result = str.match(/\(. ?\)/g)?.length;
if (result >= 2) console.log('Valid');
else console.log('Not Valid');CodePudding user response：
I want to find 2 or more instances of "(" or 2 or more instances of ")" anywhere in the string.
Are you sure this is what you mean? Intuitively it feels more likely that you would want to find 2 closed parenthesis groups. In this case you could do something like in the previous answer, although you could do it in a single regex with:
(?:.*\(.*\)){2}
https://regex101.com/r/ldaCf4/1
I want to find 2 or more instances of "(" or 2 or more instances of ")" anywhere in the string.
If this is actually what you want, as another previous answer pointed out it is perhaps not an ideal place to use a regex and it might be much clearer and simpler to use the count method, but you could do it with a regex using:
.*(?:\(.*){2}|.*(?:\).*){2}