I have a list with possibly several items (tuples) that I need to return. But what about, in the case that I only get one item in my list, I would like to return the item itself and not a list with only one item. How could this be done?

This is my code:

def strength(self):
    values = []
    max_v = 0
    my_list = []
    for i in inspect.getmembers(self):
        if not i[0].startswith('_'):
            if not inspect.ismethod(i[1]): 
                if "name" in i:
                    continue
                values.append(i[1])
                my_list.append(i)
                max_v = max(values)
    result = [tup_item for tup_item in my_list  if tup_item[1] == max_v]
    result.sort(reverse=True)
    if len(result) > 1:               
        return tuple(result)
    else:  # in case len(result) == 1
        return result  # this is where i get a list with only one item but
                       # i would like to get just the tuple itself

CodePudding user response：

If your list only has one item, it's usually at the 0th index. Just return result[0]. I would not recommend it though, since you will have to differentiate between lists and tuples from wherever you're calling that function.

CodePudding user response：

Couldnt you just return result.get(0) if size > 0