I know that my_str[1::3] gets me every 2nd character in chunks of 3, but what if I want to get every 2nd and 3rd character? Is there a neat way to do that with slicing, or do I need some other method like a list comprehension plus a join:

new_str = ''.join([s[i * 3   1: i * 3   3] for i in range(len(s) // 3)])

CodePudding user response：

I think using a list comprehension with enumerate would be the cleanest.

>>> "".join(c if i % 3 in (1,2) else "" for (i, c) in enumerate("peasoup booze scaffold john"))
'eaou boz safol jhn'

CodePudding user response：

Instead of getting only 2nd and 3rd characters, why not filter out the 1st items?

Something like this:

>>> str = '123456789'
>>> tmp = list(str)
>>> del tmp[::3]
>>> new_str = ''.join(tmp)
>>> new_str
'235689'