import random
# Define function - Number Generator
def num_gen():
num = random.randrange(1, 101)
return num
# Define function - Number Check
def num_check(x, y):
result = ''
if x > y:
result = 'high'
elif x < y:
result = 'low'
else:
result = 'correct'
return result
# Call - Number Generator
num = num_gen()
# Input - Guess
guess = int(input('Please guess a number between 1 and 100: '))
att = 1
# Process - Guess and Display Result
result = num_check(guess, num)
if result == 'high':
guess = int(input('Your guess was HIGH! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
elif result == 'low':
guess = int(input('Your guess was LOW! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
else:
print('Your guess was CORRECT! You got it in ' str(att) ' attempts!')
CodePudding user response：
After getting input from console, you should create a loop which breaks when guessed number equal to input. For example:
# Input - Guess
guess = int(input('Please guess a number between 1 and 100: '))
att = 1
# Process - Guess and Display Result
result = num_check(guess, num)
while result != guess:
if result == 'high':
guess = int(input('Your guess was HIGH! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
elif result == 'low':
guess = int(input('Your guess was LOW! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
else:
break
print('Your guess was CORRECT! You got it in ' str(att) ' attempts!')
After revision, code seems like:
import random
# Define function - Number Generator
def num_gen():
num = random.randrange(1, 101)
return num
# Define function - Number Check
def num_check(x, y):
result = ''
if x > y:
result = 'high'
elif x < y:
result = 'low'
else:
result = 'correct'
return result
# Call - Number Generator
num = num_gen()
# Input - Guess
guess = int(input('Please guess a number between 1 and 100: '))
att = 1
# Process - Guess and Display Result
result = num_check(guess, num)
while result != guess:
if result == 'high':
guess = int(input('Your guess was HIGH! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
elif result == 'low':
guess = int(input('Your guess was LOW! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
else:
break
print('Your guess was CORRECT! You got it in ' str(att) ' attempts!')
CodePudding user response：
It's because python programs runs from top to bottom, and when it reaches the bottom it's done and stops running. To stop this order we have multiple different ways:
We can call a function, as you do in you're program.
Selection Control Structures: As if statements
Iteration Control Structures: As loops
The last one is the one you need in this solution. Wrap code in a while loop, with the correct condition, in you're example, this would be
# Input - Guess
guess = int(input('Please guess a number between 1 and 100: '))
att = 1
# Process - Guess and Display Result
result = num_check(guess, num)
if result == 'high':
guess = int(input('Your guess was HIGH! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
elif result == 'low':
guess = int(input('Your guess was LOW! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
else:
print('Your guess was CORRECT! You got it in ' str(att) ' attempts!')
The best way woul be to use a will loop as follow:
while guess != num:
CodePudding user response：
You should use while True:, because your guessing code runs only once without it
import random
# Define function - Number Generator
def num_gen():
num = random.randrange(1, 10)
return num
# Define function - Number Check
def num_check(x, y):
result = ''
if x > y:
result = 'high'
elif x < y:
result = 'low'
else:
result = 'correct'
return result
# Call - Number Generator
att = 1
num = num_gen()
while True:
# Input - Guess
guess = int(input('Please guess a number between 1 and 100: '))
# Process - Guess and Display Result
result = num_check(guess, num)
if result == 'high':
print('Your guess was HIGH! Please guess another number between 1 and 100: ')
att = 1
elif result == 'low':
print('Your guess was LOW! Please guess another number between 1 and 100: ')
att = 1
else:
print('Your guess was CORRECT! You got it in ' str(att) ' attempts!')
break
CodePudding user response：
how can you expect it to run more than 1 time if you have not used any loop in the program. For example in this case you should use a while loop, then only it will prompt the user again and again and will check for the conditions, set a game variable to be True. When the number is matched then simply set the game variable to be False and it will end the loop.
import random
# Set the game variable initially to be True
game = True
# Define function - Number Generator
def num_gen():
num = random.randrange(1, 101)
return num
# Define function - Number Check
def num_check(x, y):
result = ''
if x > y:
result = 'high'
elif x < y:
result = 'low'
else:
result = 'correct'
return result
# Call - Number Generator
num = num_gen()
# Input - Guess
guess = int(input('Please guess a number between 1 and 100: '))
att = 1
# Process - Guess and Display Result
result = num_check(guess, num)
while game:
if result == 'high':
guess = int(input('Your guess was HIGH! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
elif result == 'low':
guess = int(input('Your guess was LOW! Please guess another number between 1 and 100: '))
att = 1
result = num_check(guess, num)
else:
print('Your guess was CORRECT! You got it in ' str(att) ' attempts!')
game = False