I often accidentally checkout remote tracking branches incorrectly:

git checkout -b origin/fixbugs

The -b should be a -t.

This mistake creates a branch called "origin/fixbugs". How could I get git to give me an error instead of creating this branch when the branch name begins with "origin/" (or any other remote name)?

CodePudding user response：

Since v2.28 there's a reference-transaction hook you can use to vet all such updates.

#!/bin/bash
case $1 in
prepared)
        while IFS='/ ' read old new refs type name rest; do
                if [[  $type != remotes && $new = *[^0]* ]] && git config remote.$name.url >&-
                then echo $name${rest: /$rest} would pun remote name $name
                     exit 1
                fi
        done
        ;;
esac

will do it unless you've taken to using multilevel remote names, you could beef up the check loop if you wanted.

CodePudding user response：

First, you don't have to use the -t option, since git checkout has a guess mode.

 git checkout fixbugs

If <branch> is not found but there does exist a tracking branch in exactly one remote (call it <remote>) with a matching name, and --no-guess is not specified, treat as equivalent to:

$ git checkout -b <branch> --track <remote>/<branch>

Second, use the new git switch command (with Git 2.23 , Q3 2019):

• it has the same guess mode as git checkout, so a simple git switch fixbugs is enough.
• if has a -t option, but no -b option, so you would get an error in this case!