In Typescript, what is the idiomatic way to have a boolean value assigned for each enum instance?
Say I have an enum for various error codes. For each of the error codes, I have a boolean stating if the error must be exposed to the end user or not. In Java, I would do like,
enum MyError {
ERROR1(true),
ERROR2(false),
ERROR3(false);
private boolean expose;
public boolean shouldExpose() {
return expose;
}
MyError(boolean expose) {
this.expose = expose;
}
}
Here, the boolean info (whether the error must be exposed to user or not) is encapsulated within the enum itself.
MyError myError = MyError.ERROR1;
System.out.println(myError.shouldExpose()); //true
How can I do this in Typescript as TS doesn't allow boolean values in enums? Should I use a class or a type here?
The goal is to have the boolean information contained in the enum/class/type. Hence, I don't want to create a wrapper type like
{
error: MyError
expose: boolean
}
as it can lead to wrong configuration/mappings (it becomes possible to have MyError.ERROR1 with expose as false or vice-versa for other errors).
CodePudding user response:
You wouldn't try to fit this information about the errors in the enumeration itself. The enumeration is simply for listing (well, enumerating) the errors. Their exposeness should be saved in a mapping between the error and the answer to the "is it exposed?" question.
// values don't matter; you can also skip them if you don't care for them
enum Error {
Fatal = 1,
Disk = 2,
NoInternet = 3,
}
const IS_EXPOSED: Readonly<Record<Error, boolean>> = {
[Error.Fatal]: false,
[Error.Disk]: true,
[Error.NoInternet]: true,
}
TypeScript's type system will throw an error if you miss an enumeration in the IS_EXPOSED object, so it's completely type-safe.
CodePudding user response:
You might want to give up on actual enums and instead make your own set of constants. It's more verbose but it might meet your needs.
const MyError = {
error1: {
name: 'ERROR1',
expose: true
},
error2: {
name: 'ERROR2',
expose: false
},
error3: {
name: 'ERROR3',
expose: false
}
} as const;
type MyError = typeof MyError[keyof typeof MyError]
function x(err: MyError) {
console.log(err);
}
x(MyError.error1);
x({name: 'ERROR1', expose: true});
x({name: 'ERROR1', expose: false}); // EXPECTED ERROR
function getError(): MyError {
return MyError.error1;
}
var e: MyError = getError();
console.log(MyError.error1 == e); // true
console.log(MyError.error2 == e); // false
CodePudding user response:
If you do not care about the enumerical order then you could leverage numeric enums e.g.
enum MyError {
ERROR1 = 1,
ERROR2 = 0,
ERROR3 = 0,
}
console.log(MyError.ERROR1); // 1 == true
console.log(MyError.ERROR2); // 0 == false
console.log(MyError.ERROR3); // 0 == false
console.log(Boolean(MyError.ERROR1)); // true
console.log(Boolean(MyError.ERROR2)); // false
console.log(Boolean(MyError.ERROR3)); // false
EDIT:
You could use namespace merging e.g.
namespace MyError {
export function shouldExpose(error:MyError) {
return Boolean(error);
}
}
console.log(MyError.shouldExpose(MyError.ERROR1)); // true
CodePudding user response:
You can create a class which extends the native Error class:
enum ErrorVariant {
ERROR1 = 1,
ERROR2 = 2,
ERROR3 = 3,
}
class MyError<T extends boolean> extends Error {
constructor (
readonly variant: ErrorVariant,
private readonly expose: T,
message?: string,
) {
super(message);
}
shouldExpose (): T {
return this.expose;
}
}
const myError1 = new MyError(ErrorVariant.ERROR1, false, 'Uh oh');
myError1.shouldExpose() // false
myError1.variant // ErrorVariant => 1
const myError2 = new MyError(ErrorVariant.ERROR2, true, 'Uh oh');
myError2.shouldExpose() // true
myError2.variant // ErrorVariant => 2
myError2.message // string
CodePudding user response:
It might be a good idea to use bitmask for this purpose:
enum CustomErrors {
Error1 = 1 << 0,
Error2 = 1 << 1,
Error3 = 1 << 2
}
const error_1 = 0b001
const error_1_AND_2 = 0b011
const error_1_AND_3 = 0b101
const error_3 = 0b101
const isError1 = CustomErrors.Error1 & error_1 // 1, true
const isError2 = CustomErrors.Error2 & error_1 // 0, false
const isError1_2 = CustomErrors.Error2 & error_1_AND_2 // 2, true
const isError1_2_ = CustomErrors.Error3 & error_3 // 4, true
