Regex to extract each alphanumeric pattern-CodePudding

I have a string like following

19990101 - John DoeLorem ipsum dolor sit amet 19990102 - Elton Johnconsectetur adipiscing elit

How can I write a regex that would give me these two separate strings

19990101 - John DoeLorem ipsum dolor sit amet

19990102 - Elton Johnconsectetur adipiscing elit

The regex I wrote works up to this

/\d -/gm

Image

But I don't know how can I include the alphabets there as well

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CodePudding user response：

For the OP's use case a regex based split like with ... str.split(/(?<=\w)\s (?=\d)/) ... already should do it.

The regex uses lookarounds, here trying to match any whitespace (sequence)/\s which is both led/(?<= ... ) by a word/\w and is followed/(?= ... ) by a digit/\d character.

console.log(
  '19990101 - John DoeLorem ipsum dolor sit amet 19990102 - Elton Johnconsectetur adipiscing elit 19990101 - John DoeLorem ipsum dolor sit amet 19990102 - Elton Johnconsectetur adipiscing elit'
    .split(/(?<=\w)\s (?=\d)/)
);

CodePudding user response：

You can use

const text = '19990101 - John DoeLorem ipsum dolor sit amet 19990102 - Elton Johnconsectetur adipiscing elit';
console.log(text.match(/\d \s -[A-Za-z0-9\s]*[A-Za-z]/g))
console.log(text.split(/(?!^)\s (?=\d \s -)/))

The text.match(/\d \s -[A-Za-z0-9\s]*[A-Za-z]/g) approach is extracting the alphanumeric/whitespace chars after \d \s - pattern. Details:

\d - one or more digits
\s - one or more whitespaces
- - a hyphen
[A-Za-z0-9\s]* - zero or more alphanumeric or whitespace chars
[A-Za-z] - a letter

The text.split(/(?!^)\s (?=\d \s -)/) splitting approach breaks the string with one or more whitespaces before one or more digits one or more whitespaces -:

(?!^) - not at the start of string
\s - one or more whitespaces
(?=\d \s -) - a positive lookahead that matches a location that is immediately followed with one or more digits one or more whitespaces -.