How to split a string and only return remaining values?-CodePudding

I am working with a string that I would like to split and only return the remaining values.

The string looks as follows:

let str = "service.annual.returns"

I want to remove the "service" part of the string and only return "annual.returns".

I believe I can accomplish this with the .split() method, but not sure how the expression would look to get the desired result.

Will this require me to use a regular expression, or is there a simpler way that I'm simply missing?

Thank you kindly in advance.

CodePudding user response：

No need to even convert to an array:

str.substring(str.indexOf(".") 1)

CodePudding user response：

You can use slice method, and indexOf to get the index of the first dot.

let str = "service.annual.returns"
const result = str.slice(str.indexOf('.')   1)
console.log(result)

CodePudding user response：

You can use .split() followed by .slice() and then .join() like so:

let str = "service.annual.returns";
let res = str.split('.').slice(1).join('.');
console.log(res);

First, using .split('.') retruns an array like so:

['service', 'annual', 'returns']

The .slice(1) then returns a new array containing all elements from index 1 onwards:

['annual', 'returns']

The .join('.') then returns a string, which each of your elements within the array joined by a .:

"annual.returns"

Otherwise, you can use .replace() with a regular expression:

const str = "service.annual.returns";
const res = str.replace(/[^.]*\./, '');
console.log(res);

Here, the [^.]*\. means match anything that is not a ., followed by a ., and replace that with an empty string.

CodePudding user response：

const newStr = str.split(".").filter(el => el != "service").join(".")

CodePudding user response：

str.split(".").slice(1).join(".")