I have a regex \(?\ \(?49?\)?[ ()]?([- ()]?\d[- ()]?){11}

This correctly matches German phone code like

1. 491739341284
2. 49 1739341284
3. ( 49) 1739341284
4. 49 17 39 34 12 84
5. 49 (1739) 34 12 84
6. (49) (1739) 34 12 84
7. 49 (1739) 34-12-84

but fails to match 0049 (1739) 34-12-84. I need to adjust the regular expression so that it can match numbers with 0049 as well. can anyone help me with the regex?

CodePudding user response：

Try this one:

\(?\ |0{0,2}\(?49\)?[ ()]*[ \d] [ ()]*[ -]*\d{2}[ -]*\d{2}[ -]*\d{2}

https://regex101.com/r/CHjNBV/1

However, it's better to make it accept only 49 or 0049, and throw the error message in case the number fails validation. Because if someday you will require to extend the format - it will require making the regex much more complicated.

CodePudding user response：

If you want to match the variations in the question, you might use a pattern like:

^(?:\ ?(?:00)?(?:49|\(49\))|\(\ 49\))(?: *\(\d{4}\)|(?: ?\d){4})? *\d\d(?:[ -]?\d\d){2}$

Explanation

• ^ Start of string
• (?: Non capture group
  • \ ? Match an optional
  • (?:00)? Optionally match 2 zeroes
  • (?:49|\(49\)) Match 49 or (49)
  • | Or
  • \(\ 49\) Match ( 49)
• ) Close non capture gruop
• (?: Non capture group
  • * Match optional spaces
  • \(\d{4}\) Match ( 4 digits and )
  • | Or
  • (?: ?\d){4} Repeat 4 times matching an optional space and a digit
• )? Close non capture group and make it optional
• * Match optional spaces
• \d\d Match 2 digits
• (?:[ -]?\d\d){2} Repeat 2 times matching either a space or - followed by 2 digits
• $ End of string

Regex demo

Or a bit broader variation matching the 49 prefix variants, followed by matching 10 digits allowing optional repetitions of what is in the character class [ ()-]* in between the digits.

^(?:\ ?(?:00)?(?:49|\(49\))|\(\ 49\))(?:[ ()-]*\d){10}$

Regex demo