I have a regex which is matching urls which don't have quotes (double or single) at the end and have & (ampersand) in the url.

The regex i made

([^'` "\n] )\.([^ \n] )&([^ "`'\n] )(?!["'])

but it's just not taking the last word and matching the url

Take the example of picture above

google.com/cool?cool1=yes&cool2=no&cool3=no"

the url should not match as it have " in the end

but it's just not matching 'o' and matching the remaining url.

All I wanted to do is if this double quote is present in the end then just don't match the whole url.

CodePudding user response：

You need to make the lookahead active on the whole part after the ampersand. We then have the option of

• $ end of the line
  or
• (?=\s) positive lookahead for a space.

([^' "\n] )\.([^ \n] )&((?!["'])[^ "'\n]) ($|(?=\s)

See https://regex101.com/r/6ZGpSX/1

CodePudding user response：

For a match only, you can omit the capture groups, and use a negated character class and you should omit the backtick ` from the negated character class if you want to allow to match it.

[^'"\s.] \.[^\s'"&] &[^\s"'] (?!\S)

Explanation

• [^'"\s.] Match 1 non whitespace chars other than " ' .
• \. Match a dot
• [^\s'"&] Match 1 non whitespace chars other than " ' &
• & Match literally
• [^\s"'] Match 1 non whitespace chars other than " '
• (?!\S) Assert a whitespace boundary to the right

See a regex demo.