Hello in regex how can i find ONLY first two number that start with "39"?

I tried with

^(.*?)39

but it deletes the second match also. Example:

393905598787
393400048083

I want:

3905598755
3400048099

With my code, the result is this:

05598755
3400048099

The 05598755 is wrong because I have two 39s at the beginning, but I want to discard only the first 39.

CodePudding user response：

You can consume the rest of the line after you match 39 at the start of the line and use

Find What: ^39(.*)
Replace With: $1

Details:

• ^ - start of a line
• 39 - a fixed value
• (.*) - Group 1 ($1): matches the rest of the line.

See the demo settings:

If the 39 is not at the start of the line, use ^(.*?)39(.*) and replace with $1$2.

CodePudding user response：

Try this code...

Find:^\d{2}(.*) or ^\d\d(.*)
Replace with:$1

Was working for me ...