Need help remapping the keys for d2 if they match the value for id in d1
d1={'A':{'id':'a'},'B':{'id':'b'}}
d2={'a':123,'b':123}
Expected output:
{'A': 123, 'B': 123}
CodePudding user response:
You could traverse d1 and use d2 as a lookup to modify values:
for k, d in d1.items():
d1[k] = d2.get(d['id'])
Output:
{'A': 123, 'B': 123}
CodePudding user response:
This is probably what you're after
d1={'A':{'id':'a'},'B':{'id':'b'}}
d2={'a':123,'b':123}
for key, id_map in d1.copy().items(): # view over soft copy won't mutate
try:
d1[key] = d2[id_map["id"]]
except KeyError:
pass
>>> d1
{'A': 123, 'B': 123}
However, unmapped values will remain the same (ie if there is C, but no id in its mapping, or no c in d2..)
>>> d1={'A':{'id':'a'},'B':{'id':'b'},'C':{'id':'c'}}
[..]
>>> d1
{'A': 123, 'B': 123, 'C': {'id': 'c'}}
If you want to discard unmapped values, you could do so here with del d1[key] in the except or simply create a new dict to pack the keys and values into (never added if KeyError is raised)
Alternatively, if this is an error (ie. C must exist), you can simply let KeyError raise to the caller and have it deal with the consequences
