Convert CURL API command to Python API using requests and json-CodePudding

I am connecting through an API to receive data. From the website API documentation, the instructions use either two CURL methods to connect the API; however, I need to connect using python.

1st Method Curl Example

curl -d '' -X POST 'https://api.bcda.cms.gov/auth/token' \
    -H "accept: application/json" \
    -H "authorization: Basic <Client_Secret>"

My Python Conversion:

import requests
import json

url = 'https://api.bcda.cms.gov/auth/token'
       headers = {"accept": "application/json", "authorization": 'Basic',
            '<API_Key>': '<API_Secret>'}

r = requests.post(url = url, data ={}, headers = headers)
   print(r)

2nd Method Curl

curl -d '' -X POST 'https://api.bcda.cms.gov/auth/token' \
    --user <Client_Key>:<Client_Secret> \
    -H "accept: application/json"

My 2nd Python conversion code:

import requests
import json

url = 'https://api.bcda.cms.gov/auth/token'

user = {"<Client_Key>":"<Client_Secret>", "accept": "application/json"}

r = requests.post(url = url, headers = user)

print(r)

I am receiving a 403 connection error, meaning "response status code indicates that the server understands the request but refuses to authorize it."

CodePudding user response：

You should use auth parameter and not headers to convert --user option

headers = {'accept': 'application/json'}
r = requests.post(url=url, headers=headers, auth=(client_key, client_secret))