I have this code to convert a set of URLs in column B to images in column C, but i get the error :
Unable to get the Insert property of the Pictures class. My code :
Private Sub Insert_Pic()
Dim pic As String
Dim myPicture As Picture
Dim rng As Range
Dim item As Range
lRow = ActiveSheet.Cells(Rows.Count, 3).End(xlUp).Row
Set rng = Range("B3:B" & lRow)
For Each item In rng
pic = item.Offset(0, -1)
If pic = "" Then Exit Sub
Set myPicture = ActiveSheet.Pictures.Insert(pic)
With myPicture
.ShapeRange.LockAspectRatio = msoFalse
.Width = item.Width
.Height = item.Height
.Top = Rows(item.Row).Top
.Left = Columns(item.Column).Left
.Placement = xlMoveAndSize
End With
Next
End Sub
Thanks for your help
CodePudding user response:
Ok... so the algorithm in debugging is to start with something tiny, that works and then to continue.
For a beginning - take this 4 lines only and run them:
Sub TestMe()
Dim myPicAddress As String
myPicAddress = "https://www.vitoshacademy.com/wp-content/uploads/2016/02/va2.png"
Dim myPic As Picture
Set myPic = ActiveSheet.Pictures.Insert(myPicAddress)
End Sub
Then, start working on your code, putting the With-End With part to the code, that already works:
Sub TestMe2()
Dim myPicAddress As String
myPicAddress = "https://www.vitoshacademy.com/wp-content/uploads/2016/02/va2.png"
Dim myPicture As Picture
Set myPicture = ActiveSheet.Pictures.Insert(myPicAddress)
Dim item As Range
Set item = ActiveSheet.Cells(5, 5)
With myPicture
.ShapeRange.LockAspectRatio = msoFalse
.Width = item.Width
.Height = item.Height
.Top = Rows(item.Row).Top
.Left = Columns(item.Column).Left
.Placement = xlMoveAndSize
End With
End Sub
At the end, take a look at the loop and what is passed by as a picture string. Probably the error is hidden somewhere there. Have fun :]
