The question is to print the array of string in accordance with the length of strings in ascending order.

For example

input={"vellore","i","from","am"}
output=i am from vellore

Here is my code:

int n=sc.nextInt();
    sc.nextLine();
    String[] arr = new String[n];
    for(int i=0;i<n;i  ){
        arr[i]=sc.nextLine();
    }
    //System.out.println(Arrays.toString(arr));
    Arrays.sort(arr);
    for(String i: arr){
        System.out.print(i " ");
    }

Now I know that my output will come in lexical order that is as "am from i vellore", but I want to get my desired output using sort method. I tried using Collections.sort() as well by using arraylist but I still didn't get my desired output.

I want to get my output using sort method without using the normal approach by comparing the lengths of string and all.

CodePudding user response：

You want a Comparator. In this case, you specifically want to start by comparing the String lengths. I would suggest you then compare naturally (to break ties). Like,

String[] arr = { "vellore", "i", "from", "am" };
Arrays.sort(arr, Comparator.comparingInt(String::length)
        .thenComparing(Comparator.naturalOrder()));
System.out.println(Arrays.toString(arr));

Outputs (as requested)

[i, am, from, vellore]

CodePudding user response：

tl;dr

Comparator
.comparingLong( ( String s ) -> s.codePoints().count() )
.thenComparing( Comparator.naturalOrder() )

Avoid legacy type char

The Answer by Frisch is correct in suggesting the use of a Comparator. However, the method reference seen there, String::length, fails with most characters. See this example. The String#length method reports a two-character string like c