Want to extract a number included in a path so how to extract 24?-CodePudding

just wanted to extract a number included in a path path is stored in catalina_home string as "/opt/hpws24/tomcat" so How to extract 24

I tried

catahome='/opt/hpws24/tomcat'
version=$(echo "$catalina_home" | grep -o -E '[0-9] ')
echo $version

which is giving me 24 but still i want only the number which attached to hpws because my code is giving all the numbers with space separated in case opt or tomcat is having a number sttached in future, So i want only a number attached 2 hpws. please guide me

CodePudding user response：

Problem in OP's attempt is, using grep to simply find Digits in whole variable value which may lead to get false positive results too.

With your shown samples/attempts, please try following awk program.

catahome="/opt/hpws24/tomcat"
echo "$catahome" | awk -F'/' '{sub(/[^0-9] /,"",$3);print $3}'

Explanation: Printing value of string with echo command and sending its output as a standard input to awk command. In awk program, using -F option to set field separator as / for all the lines. In main program using sub function of awk to substitute everything apart from digits with NULL and printing 3rd column then.

CodePudding user response：

You did a small mistake

version=$(echo "$catalina_home" | grep -o -E '[0-9] ')

should be

version=$(echo "$catahome" | grep -o -E '[0-9] ')

Here the output that i got

nabil@LAPTOP~$ catahome='/opt/hpws24/tomcat'
nabil@LAPTOP:~$ version=$(echo "$catahome" | grep -o -E '[0-9] ')
nabil@LAPTOP:~$ echo $version
24