how to filter array items in js without filter method?-CodePudding

here is the question

Filter out companies which have more than one 'o' without the filter method
0: "Facebook" 1: "Google" 2: "Microsoft" 3: "Apple" 4: "IBM" 5: "Oracle" 6: "Amazon"

CodePudding user response：

u need to loop through the array and verifie if each word has more than one "o"

her is a function to verifie the word:

const verif=(word)=>{
    var s=0
    var l=word.length
    for(let i=0 ; i<=l;i  ){
        if(word[i]=="o"){
            s  
        }
    }if(s>=2){
        return true
    }else{
        return false
    }
}

CodePudding user response：

You can create a function a iterate through each array element

    function filterArray(arr, fn) {

    let filteredArray = [];
    for (let i = 0; i < arr.length;   i) {
        if (fn(arr[i]) === true) {
            filteredArray.push(arr[i]);
        } 
    }
    return filteredArray;
}

function isIsogram (str) {
    return !/(.).*\1/.test(str);
}

const arr = ["Facebook", "Google", "Microsoft", "Apple", "IBM", "Oracle", "Amazon"];
console.log(filterArray(arr, isIsogram));

CodePudding user response：

You could write a loop.

const values = [
  "Facebook", "Google", "Microsoft",
  "Apple", "IBM", "Oracle", "Amazon"
];

const result = [];
for (const value of values) {
  if ((value.match(/o/g) || []).length > 1) result.push(value);
}
console.log(result);

You could use reduce().

const values = [
  "Facebook", "Google", "Microsoft", 
  "Apple", "IBM", "Oracle", "Amazon"
];

const result = values.reduce((acc, val) => {
  if((val.match(/o/g) || []).length > 1) acc.push(val);
  return acc;
}, []);

console.log(result);

But it is better to stick with filter().

const values = [
  "Facebook", "Google", "Microsoft",
  "Apple", "IBM", "Oracle", "Amazon"
];

const result = values.filter(v => (v.match(/o/g) || []).length > 1);
console.log(result);