using Tail and Grep to select a specific phrase within a double quotation-CodePudding

currently I am tail and grep a live log but would like to grep the entire url within the double quotation ...

Current tail i've put together

tail -F trans.log | grep --color -E -i "https://www.example.com|$"

Log

1.1.1.1 6 - [21/Jan/2022:16:41:21  0000] "GET /media/catalog/product/cache/####.jpg HTTP/1.1" 304 - "https://www.example.com/customer/" "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/97.0.4692.71 Safari/537.36"

Desired output:

for grep https://www.example.com/customer/ would be highlighted during the live log Tail

CodePudding user response：

Converting my comment to answer so that solution is easy to find for future visitors.

You may use this command:

tail -F trans.log | grep --color -ioE 'https://www\.example\.com[^"]*'

Pattern https://www\.example\.com[^"]* matches a substring starting with https://www.example.com followed by 0 or more non-" characters.