in Linux bash I see script using |& operator like:

/opt/program.sh |& tee -a /var/log/program.log

What is the meaning of |& operator?

Regards

CodePudding user response：

Per §3.2.3 "Pipelines" in the Bash Reference Manual, |& is similar to |, except that:

If ‘|&’ is used, command1’s standard error, in addition to its standard output, is connected to command2’s standard input through the pipe; it is shorthand for 2>&1 |. This implicit redirection of the standard error to the standard output is performed after any redirections specified by the command.

That is — anything that /opt/program.sh prints to standard output or to standard error will be piped into tee -a /var/log/program.log.

CodePudding user response：

In addition to ruakh's answer, here are some tries, as completion of In the shell, what does " 2>&1 " mean?

ls -ld /t{mp,nt} | wc
ls: cannot access '/tnt': No such file or directory
      1       9      49

ls -ld /t{mp,nt} 2>&1 | wc
      2      18     101

ls -ld /t{mp,nt} |& wc
      2      18     101

But as command line order is important, this will be treated as last redirection:

ls -ld /t{mp,nt} 2>&1 1>/dev/tty | wc
drwxrwxrwt 11 root root 4096 Jan 19 08:39 /tmp
      1       9      52

ls -ld /t{mp,nt} 1>/dev/tty |& wc
      0       0       0
ls: cannot access '/tnt': No such file or directory
drwxrwxrwt 11 root root 4096 Jan 19 08:39 /tmp