I've list like this.
list = ['As Michael Harvey writes, paragraphs are “in essence—a form of punctuation, and like other former. ',
'',
'Many novice writers tend to make a sharp distinction between content and style, thinking that a paper can be strong']
As we can observer there is an empty list ''. I want to split my list based on the empty list.
Expected output:
#input
input list=['some text ', '', 'some texts example']
Output:
list1= ['some text ']
list2= ['some text example']
CodePudding user response：
Go over each element in the list en remove it when there is an element with length 0.
l = ['As Michael Harvey writes, paragraphs are “in essence—a form of punctuation, and like other former. ',
'',
'Many novice writers tend to make a sharp distinction between content and style, thinking that a paper can be strong']
output = [ele for ele in l if len(ele) > 0]
list1, list2 = output
This works for your example, but it does not "split" on the empty element. Then you can use a for loop:
output = ['']
for ele in l:
if len(ele) > 0:
output[-1] = ele
else:
output.append('')
This last part splits your list:
l = ['a', 'b', '', 'c']
output = ['']
for ele in l:
if len(ele) > 0:
output[-1] = ele
else:
output.append('')
# output = ['ab', 'c']
Edit: output as lists:
l = ['a', 'b', '', 'c']
output = [[]]
for ele in l:
if len(ele) > 0:
output[-1].append(ele)
else:
output.append([])
# output = [['a', 'b'], ['c']]
If you have more lists it stops here since output can be as large as you want. If you know the result is two lists you can unpack them:
lst1, lst2 = output
sidenote: do not use variable list since it is a data structure in python.
CodePudding user response：
Super basic solution. Allows for splitting of more than two sentences. Output in sentences variable, a list of lists.
list = ['a','','b','','c']
sentences = []
for s in list:
if len(s)!=0:
sentences.append([s])
There are better and faster solutions in other answers here, this one just details a not-so-technical/beginner friendly solution.
CodePudding user response：
If you know how many lists you are going to have:
list1, *list2 = (i for i in input_list if i)
otherwise, in case you do not know how many lists you are going to end up with, you will probably end up with a dict or a list of list's
CodePudding user response：
You can use a dictionary of lists.
l = ['As Michael Harvey writes, paragraphs are “in essence—a form of punctuation, and like other former. ',
'',
'Many novice writers tend to make a sharp distinction between content and style, thinking that a paper can be strong']
lists = dict()
x = 1
for ele in l:
if(len(ele) > 0): # checking if the length of the element in l is sufficient (larger than 0)
lists[x] = [ele] # adding a list with the element to the dictionary
x = 1
Output:
lists[1] = ['As Michael Harvey writes, paragraphs are “in essence—a form of punctuation, and like other former. ']
lists[2] = ['Many novice writers tend to make a sharp distinction between content and style, thinking that a paper can be strong']
CodePudding user response：
You can use the below-attached snippet for that.
list = ['As Michael Harvey writes, paragraphs are “in essence—a form of punctuation, and like other former. ',
'',
'Many novice writers tend to make a sharp distinction between content and style, thinking that a paper can be strong']
out = [[i] for i in list if i!='']
# Printing each list
for i in out:
print(i)
