Guys I have these two REGEX but I couldn't join them.
I need it not to have a leading zero and contain from 1 to 4 or 9 characters.
Accept:
1
12
10
123
103
1234
1004
123456789
456004500
Not:
01 (leading zero)
003 (leading zero)
0234 (leading zero)
12345 (5 characters)
1234567891 (10 characters)
^(?!0{1})[0-9]{9}$
^([0-9]{1}|[0-9]{2}||[0-9]{3}||[0-9]{4}|[0-9]{9})$
CodePudding user response：
Use [1-9] to match the first character. Then match the remainder the appropriate number of times to get 1-4 or 9 total digits.
^[1-9]([0-9]{0,3}|[0-9]{8})$
CodePudding user response：
Use
^(?!0)(?:\d{1,4}|\d{9})$
See regex proof.
EXPLANATION
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^ the beginning of the string
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(?! look ahead to see if there is not:
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0 '0'
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) end of look-ahead
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(?: group, but do not capture:
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\d{1,4} digits (0-9) (between 1 and 4 times
(matching the most amount possible))
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| OR
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\d{9} digits (0-9) (9 times)
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) end of grouping
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$ before an optional \n, and the end of the
string