I wrote a C function that receives a string from the user, and replaces the letter with the highest frequency, with the letter with the second highest frequency in the string.
Example: For the input i love you more, the string i levo yeu mero will be returned
#include <stdio.h>
#include <string.h>
void stringReplace(char str1[]);
int main()
{
char str1[100] = { 0 };
stringReplace(str1);
return 0;
}
void stringReplace(char str1[])
{
char ch1, ch2;
int i, h, j, p, n, len, counter1 = 0, counter2 = 0, first, second, times;
printf("Please enter the string - maximum = 100 characters:\n");
printf("User input: ");
fgets(str1, 100, stdin);
str1[strcspn(str1, "\n")] = 0;
len = strlen(str1);
for (i = 0; i < len; i ) {
counter1 = 0;
for (j = 0; j < len; j ) {
if (str1[i] == str1[j]) {
counter1 ;
}
if (counter1 > counter2) {
first = i;
}
}
counter2 = counter1;
} //character which shows up most - found.
counter2 = 0;
for (p = 0; p < len; p ) {
for (n = 0; n < len; n ) {
if (str1[p] == str1[n]) {
counter1 ;
}
if (counter1 < first && counter1 > counter2) {
second = p;
}
}
counter2 = counter1;
}
ch1 = str1[first];
ch2 = str1[second];
for (h = 0; h < len; h ) {
if (str1[h] == ch1) {
str1[h] = ch2;
}
}
puts(str1);
}
This is the code I have done, and instead of changing the string it prints the same thing. for example:
Please enter the string - maximum = 100 characters:
User input: i love you more
i love you more
CodePudding user response:
Suggest : divide and conquer with helper functions.
Think about the sub-problem: Counting the 1st & 2nd most popular.
Walk the string. At each character count its occurrence with the rest of the string. O(n*n)
When a better than 2nd place count is detected, adjust 1st and 2nd place.
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
void most_popular2(const char *s, char pop[2]) {
pop[0] = pop[1] = 0;
size_t pop_count[2] = {0, 0};
while (*s) {
// Do not count white-space.
if (!isspace(*(const unsigned char* )s)) {
// How popular is *s?
size_t count = 1;
// sum all the matches on the rest of the string
for (const char *r = s 1; *r; r ) {
if (*s == *r) {
count ;
}
}
// Test if better than the 2nd most popular.
if (count > pop_count[1] && *s != pop[0]) {
if (count > pop_count[0]) {
// Demote 1st place to 2nd place.
pop_count[1] = pop_count[0];
pop[1] = pop[0];
// Save new 1st place.
pop_count[0] = count;
pop[0] = *s;
} else {
// Save new 2nd place.
pop_count[1] = count;
pop[1] = *s;
}
}
}
s ;
}
}
Sample
int main() {
char s[] = "i love you more i love you more\n";
char pop[2];
most_popular2(s, pop);
printf("1st:%c 2nd:%c\n", pop[0], pop[1]);
}
Output
1st:o 2nd:e
Leave it to OP to take the 2 most popular characters and form the desired output.
More efficient code could copy the string, sort it O(n*(lng(n)) and then walk it to find the 2 most popular.
CodePudding user response:
thanks for the help, now i got it. this is what i did:
#include <stdio.h>
#include<stdio.h>
#include<string.h>
#define ASCII_A 97 // ascii for A is 97
#define MAXSIZE 50 // max size for string
#define ALPHABETS 26 //total number of alphabets
void stringReplace(char s[], int a[]);
int main()
{
char s[MAXSIZE] = {0};
int a[ALPHABETS] = {0}
stringReplace(s);
return 0;
}
/*
function to replace the most common charcter with the second one
input: the string
output: none
*/
void stringReplace(char s[], int a[])
{
int i;
int count = 0;
int max = 0, max2 = 0;
int index, index2;
printf("Enter the string:\n");
fgets(s, MAXSIZE, stdin);
s[strcspn(s, "\n")] = 0;
for(i=0; i<26; i ) // initialize all array elements to zero
{
a[i]=0;
}
for(i=0; i<strlen(s); i ) // loop for traversing the string
{
a[s[i]-ASCII_A] ; // increment by 1 for each occurrence.
}
for(i=0; i< ALPHABETS; i ) //prints alphabets and occurrence.
{
count = a[i];
if (count > max)
{
max = count;
index = i;
}
if(count < max && count > 1)
{
max2 = count;
index2 = i;
}
}
printf("%c\n", ASCII_A index);
printf("%c\n", ASCII_A index2);
}
