I have declared a map in bash like the following
declare -A myMap
myMap=( [A:B:C:D]=813.0 [P:Q:R:S]=2346957.02 [W:X:Y:Z]=53831.93 [E:F:G:H]=113770.0)
I want to split the string in Key having delimiter (:) and get the output in descending order of value like this
P - Q - R - S - 2346957.02
E - F - G - H - 113770.0
W - X - Y - Z - 53831.93
A - B - C - D - 813.0
The code I am trying is the following
for k in "${!myMap[@]}"
do
arrIN=(${k//:/ })
echo ${arrIN[0]} ' - ' ${arrIN[1]} ' - ' ${arrIN[2]} ' - ' ${arrIN[3]} ' - ' ${myMap["$k"]}
done | sort ${myMap["$k"]}
But the output using my code is this
E - F - G - H - 113770.0
W - X - Y - Z - 53831.93
P - Q - R - S - 2346957.02
A - B - C - D - 813.0
Is there an easy way to achieve this?
CodePudding user response:
If you print the original key and the value, sort by the second column (k2), numeric reverse.
#! /bin/bash
declare -A myMap
myMap=( [A:B:C:D]=813.0 [P:Q:R:S]=2346957.02 [W:X:Y:Z]=53831.93 [E:F:G:H]=113770.0)
for k in ${!myMap[@]} ; do
echo $k ${myMap[$k]}
done | sort -rnk2 | sed 's/[: ]/ - /g'
If you split the key, you need to sort by the ninth column:
for k in "${!myMap[@]}" ; do
arrIN=(${k//:/ })
echo ${arrIN[0]} - ${arrIN[1]} - ${arrIN[2]} - ${arrIN[3]} - ${myMap[$k]}
done | sort -nrk9
CodePudding user response:
Alternate method using the file name globbing to sort keys.
#!/usr/bin/env bash
declare -A myMap
myMap=( [A:B:C:D]=813.0 [P:Q:R:S]=2346957.02 [W:X:Y:Z]=53831.93 [E:F:G:H]=113770.0)
tmpDir=
trap 'rm -fr "$tmpDir"' EXIT INT
tmpDir=$(mktemp -d)
myKeys=("${!myMap[@]}")
# Create a file per key in the temp directory
touch "${myKeys[@]/#/$tmpDir/}"
# Load keys from temp directory benefiting from auto sorting
myKeys=("$tmpDir/"*)
# Strip file path from keys
myKeys=("${myKeys[@]##*/}")
# Iterate keys in reverse order
for (( i=${#myKeys[@]}-1; i>=0; i-- )); do
k=${myKeys[i]}
# Split key by :
IFS=: read -ra ka <<<"$k"
# Get corresponding value
v=${myMap[$k]}
# Print joined key elements with " - " followed by value
printf '%s%s%s%s%s\n' "${ka[@]/%/ - }" "$v"
done
